The graph of a quadratic function has a vertex at (5,3) and goes through the point (-1,-9). What is the equation of the function? o
f(x)= -3(x - 5)2 + 3
f(x)=-} (x – 5)2 + 3
f(x)= -(x + 5)2 + 3
f(x)=–3(+ 5)2 + 3

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

49/6 is going to equal 8 1/6

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )