A moving company has boxes numbered 1 through 40. What is the probability that the first box chosen by a mover is not a multiple of 9?

a is the right answer

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

i believe it is d.) buddhism and e.) hinduism

"exterior angles = 360 / number of sides.

60 = 360 / sides

sides = 360 / 60

sides = 6"