ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 - 5j ohms. Add these complex numbers to find the total impedance in the circuit.
=j ohms

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.