Calculate the slope of a line that passes through the following two points. (5,-2) and (4, -8)
help please it’s due tonight

the slope is 6 (6/1)

Step-by-step explanation:

Use the slope formula: y2-y1/x2-x1 ( i did the one that was further to the right ats the second pair rather than the order that you put it in)

Yo, the slope of the line is 6 yo!

Step-by-step explanation:

You see, to find the slope of 2 points, Here's what ya do little fella: Pick any y-coordinate point(-2) or (-8). When you do, subtract -2 and -8 so in this case,      -y - (-x) = -y + x. So, when done correctly, you get 6 because -2 - (-8) is equal to -2 + 8. Ya go to the x-coordinate. If you subtracted -8 from -2, you have to subtract 4 from 5. If you also subtracted -2 from 8, you have to subtract 5 from 4. So, it has to be in order. 5 - 4 = 1. So then, you divide your answer 6/1 = 6. So 6 is the slope people. NA YOU PEOPLE EHN, YA BETTER GO AND START LEARNING ALGEBRA.

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step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2