What mass of iron(III) chloride contains 4.13 x 10^23 chloride ions?

iron (III) chloride's chemical formula is FeCl₃  Since Fe (III) is Fe³⁺ and Cl is Cl⁻.  Given that, you know that 3 moles of Cl⁻ combine with 1 mole of FeCl₃.  

First, you need to find the number of moles of Cl⁻ is contained in  2.35x10^23 atoms of Cl⁻.  To do this you need to divide the number of Cl⁻ atoms by Avogadro's number (6.02x10^23atoms/mol) to get 0.3902 moles of Cl⁻.  Then you multiply 0.3902 by 1/3 (using the fact that there is 1mol Fe³⁺ per 3mol Cl⁻) to get the number of moles of FeCl₃ which is 0.1301mol FeCl₃.  Then to find the mass FeCl₃, you need to multiply the number of moles of FeCl₃ (which is 0.1301mol) by the molar mass of FeCl₃ (which is 162.15g/mol) to get 21.09g FeCl₃.

therefore the amount of FeCl₃ is 21.09g FeCl₃.

Step-by-step explanation:

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!