Find the solution(s) of the quadratic equation x2 + 2x -15 = 0. A)x= -5,3
B)x= 5,3
C)x= -5 -3
D)x= 5,-3

The answer is A.

Step-by-step explanation:

Let's solve your equation step-by-step.

x2+2x−15=0

Step 1: Factor left side of equation.

(x−3)(x+5)=0

Step 2: Set factors equal to 0.

x−3=0 or x+5=0

x=3 or x=−5

x=3 or x=−5

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

answer: this is not a question

step-by-step explanation: this is a answer