Show work Bonita and Vince are jogging to school 2.5 miles west of

Vinces' house. It takes

them 15 minutes to arrive. As soon as they got there Boneta needed to run east

5 miles to the discount store for personal supplies. This took her 5 minutes. She

then slowly walks back to school, which takes her another 10 minutes

What is the average velocity in miles/min for Bonita for the entire trip?

Show how you convert this to mis? Show your setup and answer.

What is her average speed in miles/min?

- Show how you convert the average speed to mis. Show your set up and answer.

V_avg = 0.5556 miles/min

V_avg = 0.00926 miles/sec

Step-by-step explanation:

Bonita jogs 2.5 miles west of Vinces' house to school. It took her 15 minutes to arrive.

Speed 1; distance/time = V1 = 2.5/15 = 1/6 miles/min

Furthermore she ran 5 miles to the discount store for personal supplies. This took her 5 minutes.

Thus;

Speed 2; V2 = 5/5 = 1 mile/min

She then slowly walks back to school, which takes her another 10 minutes. Distance from the discount stor to school is 5 miles as stated in speed 2.

Thus;

Speed 3: V3 = 5/10 = ½ mile/min

Her average speed is;

V_avg = (V1 + V2 + V3)/3

V_avg = (1/6 + 1 + ½)/3

V_avg = 10/18 = 0.5556 miles/min

Converting to miles/seconds

60 seconds make 1 minutes, therefore 1 mile/min = 1/60 miles/seconds

Thus;

V_avg = 0.5556 miles/min = 0.5556 × 1/60 miles/sec = 0.00926 miles/sec

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation:

i would pic false cause it goes down towards negative

step-by-step explanation: