The roots of 3x^2+kx+12=0 are equal, find k.

Step-by-step explanation:

3x^2+kx+12=0

k= -3x-12/x

k = 12  

Step-by-step explanation:

3(x² + kx + 2²) = 3(x² + x + 4) = 3(x² + 4x + 4) = 3x² + 12x + 12 ⇒ k = 12

idk

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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