What is the area of the region bounded by the graph of the equation x^2+y^2 + 3 = -4y + 6x-1?

9π

Step-by-step explanation:

What we need  to do here is convert this equation into a standard circle equation;

x^2+y^2 + 3 = -4y + 6x-1,

x^2+y^2+4y-6x+1 = 0,

x^2-6x+(-3)^2 + y^2+4y+(2)^2  = 3^2

(x-3)^2 + (y+2)^2 = 3^2,

so we have a circle with a radius of 3, and hence the area of our region is π(3)^2 = 9π. correct!

m a t h w a y. c o m

step-by-step explanation:

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