Bina Chand bought two kettle for rs 1625.she sold one of them at 20% profit and the other at 20% loss. if the selling price of both kettle are same .find the cost price of each kettle .Also calculate her gain or loss percent in the total transaction.

cost of each kettle:

gain/loss from each transaction:

total loss = 65

loss % = 4%

Step-by-step explanation:

both kettles cost 1625

K₁ + K₂ = 1625

selling price of K₁ = [(100 + 20) / 100] x K₁ = 1.2K₁

selling price of K₂ = [(100 - 80) / 100] x K₂ = 0.8K₂

1.2K₁ = 0.8K₂

K₁ = 1625 - K₂

K₁ = 0.8K₂ / 1.2

1625 - K₂ = ²/₃K₂

1625 = ²/₃K₂ + K₂ = ⁵/₃K₂

K₂ = 1625 x ³/₅ = 975

K₁ = 1625 - K₂ = 1625 - 975 = 650

selling price = 1.2K₁ = 1.2 x 650 = 780

selling price K₂ = 0.8K₂ = 0.8 x 975 = 780

gain from selling K₁ = 780 - 650 = 130

loss from selling K₂ = 780 - 975 = 195

total loss = 195 - 130 = 65

loss % = 65 / 1625 = 0.04 = 4%

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: