Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1? f(x) = 3x2 + 5x + 4 f(x) = 3x2 + 15x + 12 f(x) = 3x2 – 5x + 4 f(x) = 3x2 – 15x + 12

f(x) = 3x^2 - 15x + 12

Step-by-step explanation:

All of the second degree polynomials listed have a leading coefficient of 3.

Since we are asked which has roots 4 and 1, we know we need to find the polynomial where x is a negative number, then solve for x.

f(x) = 3x^2 - 15x + 12

= 3(x^2 - 5x + 4)  --- Here, I factored out the 3.

= 3((x-4)(x-1)) --- solve for the quadratic.

Therefore, solving for x, we have

x - 4 = 0    and  x - 1 = 0

x = 4                  x = 1

Thus, this polynomial has a lead coefficient of 3 and its roots are 4 and 1.

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation: