A survey was given to a random sample of 1750 voters in the United States to ask about their preference for a presidential candidate. Of those surveyed, 52% of the people said they preferred Candidate A. Determine a 95% confidence interval for the proportion of people who prefer Candidate A, rounding values to the nearest thousandth. Find the margin of error.

x = -2

y = 848

step-by-step explanation:

plug in the numbers

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!