What is the y-intercept of the equation of the line that is perpendicular to the line v= x -x+ 10 and passes through the point (15,-5)?
O y=xx-20
O y=-3x+20
Ov=3x-2
Ov=-3x+20

Here, m=-5/3, and b=y-intercept=20

Here, the y-intercept is: 20

Thus, option (d) is true.

Step-by-step explanation:

Given the equation

comparing the equation with the slope-intercept form

Here,

so the slope of the line is 3/5.

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be: -5/3

Therefore, the point-slope form of the equation of the perpendicular line that goes through (15,-5) is:

simplifying the equation to convert it into the slope-intercept form

We know that the slope-intercept form of the line equatio is

here 'm' is the slope and 'b' is the y-intercept

subtract 5 from both sides

Here, m=-5/3, and b=y-intercept=20

Here, the y-intercept is: 20

Thus, option (d) is true.

step-by-step explanation: