What is the point-slope form of the equation of the line that passes through the point (-3,-4) and has a slope of 2?

y=2x+2

Step-by-step explanation:

To find the point-slope form of the equation we need to get the slope-intercept form of (-3,-4) and 2

(Slope intercept form formula is y=mx+b) (m is slope) (b is y-intercept)

So we know that the slope of this equation is 2 so we can replace m with 2 since the slope is 2 and m is slope.

Equation will look like this:

y=2x+b

Now we need to find the b or y-intercept of the equation to do this the (-3,-4) come into play: replace x with -3 and replace y with -4

(x,y) -3 is x since it is the same spot in (-3,-4) and -4 is y since it is in the same spot in (-3,-4)

Replace:

-4=2(-3)+b

Multiply 2 and -3:

-4=-6+b

Move 6 to the other side by adding 6 on both side:

6-4=-6+6+b

Simplify

2=b

Now the equation looks like this: (If you replace b with 2 in y=2x+b)

y=2x+2

y=2x+2 (Point-slope form is the same thing as slope-intercept form)

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.