Mathematics, 04.12.2020 18:20 mathhelper22
Semester Review Day 4
Solve for the variable
(2x + 1)^
33
Answers: 1
Mathematics, 22.06.2019 01:00
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
Answers: 3
Mathematics, 22.06.2019 01:10
Use a standard normal table to determine the probability. give your answer as a decimal to four decimal places. β1.5< < 1.5)
Answers: 3
Mathematics, 22.06.2019 01:30
Im so bad at fractions they are not my best math thing to work on
Answers: 1
Semester Review Day 4
Solve for the variable
(2x + 1)^
33
...
Solve for the variable
(2x + 1)^
33
...
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