Find three consecutive odd integers such that the difference of thrice the smallest and twice the largest is -19

Answer:

Step-by-step Explanation:

Let the three consecutive odd integers be x, x + 2 and x + 4 because odd integers are in the gap of 2.

GiveN:

This can be written as:

➛ 3(x) - 2(x + 4) = -19

➛ 3x - 2x - 8 = -19

➛ x - 8 = -19

➛ x = -11

Then:

The consecutive odd integers are:

366

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.