A particle travels along the x-axis such that its position at time t is given by the function x(t)= 2t^2+t. What is the average speed of this particle over the interval 2 is less than or equal to t which is less than or equal to 10 A-4

B-200

C-32

D-25

4: A

Step-by-step explanation:

Mathematically, the average speed over a particular range will be;

f’(b)-f’(a)/(a-b)

In this case; a = 2 and b = 10

So we have the following;

f’(x) = 4t + 1

f’(10) = 4(10) + 1 = 41

f’(2) = 4(2) + 1 = 9

So we have the average speed change as;

(41-9)/(10-2)

= 32/8 = 4

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: