Find the amount of interest on $6200 with an interest rate of 3.5% a year. How much do I have in total for 4 years?

$868

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 3.5%/100 = 0.035 per year,

then, solving our equation

I = 6200 × 0.035 × 4 = 868

I = $ 868.00

The simple interest accumulated

on a principal of $ 6,200.00

at a rate of 3.5% per year

for 4 years is $ 868.00.

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b