If isosceles triangle ABC has a 130° angle at vertex B, which statement must be true? OmZA = 15° and mZC = 35°
mZA = 25° and mZC = 25°
OmZA = 20° and mZC = 30°
OmZA + m ZB = 155° and mZC = 60°

m∠A = 25° and m∠C = 25°

Step-by-step explanation:

The sum of all three angles in a triangle must add up to 180°.  Since the measure of angle B is 130°, the sum of the other two angles have to be 50°.  

Also, the triangle is isosceles, meaning two of the sides are equal in length.  For those sides, their corresponding angles must also be equivalent.  In this case, it's the two smaller angles.  Since we have 50° between the two angles, A and C, divide 50 by 2 to get 25° for both angle measurements.  

m∠A+ m∠B = 155°

Step-by-step explanation : ill give all the answers to test

1. B

2. D

3. B

4. D

5. A

6. B

7. A

8. B

9. C

10. D

11. A

12. C

13. D

14. D

15. D

16. A

17. D

18. D

19. A

20. B

21. C

22. B

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step-by-step explanati∵∵∴∴on:

a

b

d

step-by-step explanation: