Teri begins walking east at 2 miles per hour at 1:00 pm. If cindy leaves from the same point 30 minutes later walking east at 3 miles per hour, when will she catch teri

One hour after  starting

Step-by-step explanation:

Let Teri walk at a rate of 2 miles per hour in time , t + 0.5, since it is 30 minutes ahead and 30 minutes = 0.5 hours, the distance he moves is d = 2(t + 0.5). Also, since Cindy moves at a rate of 3 miles per hour, and starts at time t, the distance d' she moves is d' = 3t.

Now, when they catch each other, the distance moved is the same.

So, d = d'

2(t + 0.5) = 3t

expanding the brackets, we have

2t + 2 × 0.5 = 3t

2t + 1 = 3t

collecting like terms, we have

3t - 2t = 1

simplifying, we have

t = 1

So, Cindy will catch Teri one hour after starting.

step-by-step explanation:

a

step-by-step explanation: