In ∆TMZ, the measure of angle M is 6° more than twice the measure of angle T, and the measure of angle Z is 50° less than five times the measure of angle T.

m<T = , m<M = and m<Z =

Step-by-step explanation:

From the given ∆TMZ, let the measure angle T be represented by T.

So that,

m<M = 2T + 6°

m<Z = 5T - 50°

Sum of angles in a triangle =

T + (2T + 6°) + (5T - 50°) =

8T - =

8T = +

    =

T =

   =

Therefore,

i. m<T =

ii. m<M = 2T + 6°

        = 2 x + 6°

        =

m<M =

iii. m<Z = 5T - 50°

            = 5 x - 50°

            = - 50°

            =

m<Z =

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

isocolese triangle

we know that the line connect a and b is the hyptonuse

so first find the hypotonuse length using the distance formula, call the length c

since it is an isocolese triangle, the lengths of the legs are the same

using pythagorean theorem,

in this case, a=b since isocolese triangle so we get

or

we can find c so we can find the distances

we know that if we draw 2 circles, each has center at a and b, and find where they intersect, we can the 2 possible locations for c

if a has center at (xa,ya) and b has center at (xb,yb), then we can solve where

and

intersect to find where they intersect

i'm not going to put an example because i have to go to class. i hope this explanation is enough