HELP I HAVE A CLASS SOON 3 and 4!!

Given: FT = FR
SF bisects 2 TFR
Prove: TES RFS

ΔTFS ≅ ΔRFS (sas) because:

+) FT = FR (given)

+) FS ≅ FS (in the picture)

+) ∠TFS = ∠RFS ( SF bisects ∠TFR)

Step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

after going and makeing graphs i would go with a,

there is nothing that is matches the graph. if there was i would show you. but therefore my answer is a.

hope i

-lavira: )