What is the equation of the line that passes through the point (2, -1) and has a
slope of 3/2

y = 3/2x - 4

Step-by-step explanation:

y = mx + b

*plugging in slope*

y = 3/2x + b

*finding b (aka y-intercept, starting value, when x=0) by plugging in x and y values from point (2, -1) )*

-1 = 3/2 * 2 + b

-1 = 3 + b

b = -4

so: y = 3/2x - 4

Given :-

A line having a slope of 3/2 passes through (2,-1) .

To Find :-

The equation of the line .

Answer :-

According to the question ,

m = 3/2

Point = (2,-1)

We know Point slope form of the line as ,

y - y¡ = m ( x - x ¡ )

Substitute ,

y - (-1) = 3/2 ( x - 2 )

y + 1 = 3/2x - 3/2*2

y +1 = 3/2x - 3

2( y +1) = 3/2x *2 - 3*2

2y + 2 = 3x - 6

3x -2y -8 = 0

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,