The area of a rectangular warehouse measures 4,288 square feet. The width of the warehouse is 64 feet long. Draw a model to represent the problem, and then solve for the length of the warehouse. Use paper to show your work.

Length is 67

Step-by-step explanation:

For the show your work bit, your gonna wanna divide 4288 by 64 to get 67 as your length. Then draw your rectangle with the 64 square feet on one side and put a w next to it. Then on the next side write 67 square feet with an L next to it. Hope this helped!!

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.