9. Evaluate the ceiling function for the given value. A. f(x) = ⌈x⌉; x = −7.4

B. g(x) = ceiling (x, 0.50);
x = 21.27

Given:

A. f(x) = ⌈x⌉; x = −7.4

B. g(x) = ceiling (x, 0.50);  x = 21.27

To find:

The values of ceiling function for the given value.

Solution:

A.

We have,

f(x) = ⌈x⌉; x = −7.4

Here, f(x) is a ceiling function, so we need to find the nearest next integer value because if m < x ≤ n, then ⌈x⌉ = n, where m and n are integers.

Now,

f(-7.4) = ⌈-7.4⌉

f(-7.4) = -7

Therefore, the value of f(x) is -7 at x=-7.4.

B.

g(x) = ceiling (x, 0.50);  x = 21.27

Here, g(x) is a ceiling function with 0.50, so we need to find the nearest next multiple of 0.50 because if m < x ≤ n, then ⌈x⌉ = n, where, m and n are multiples of 0.50.

Now,

g(21.27) = ceiling (21.27, 0.50)

g(21.27) = 21.50

Therefore, the value of g(x) is 21.50 at x=21.27.

correct answer:

i^31 = -i

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)