6. A ball is thrown at an upward velocity of 72 feet per second from a platform that is raised 10 feet off the ground. Use the equation y = -12 + vt + h where y is the ending height of the ball, t is the
time in seconds, v is the ball's velocity, and h is the intial height, in feet, of the ball.
How long will it take the ball to reach its maximum height, and what is that maximum height?
(Disregard any extra height added by the person throwing the ball.)

Question 675528: A ball is thrown vertically upward with an initial velocity of 48 feet per second. If the ball started its flight at a height of 8 feet, then its height s at time t can be determined by s(t)=-16t^2+48t+8 where s(t) is measured in feet above the ground and t is the number of seconds of flight.

Step-by-step explanation:

answer: need picture of problem

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

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