Sin x > -√3/2 please Solve in R inequation:

(4π/3+2πn; 5π/3+2πn)

Step-by-step explanation:

1. to calculate the zeros:

sinx=-sqrt(3)/2; ⇔

, where n∈Z.

2. using the zeros found and the attached picture:

x∈(4π/3+2πn; 5π/3+2πn).

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!