What is the sum of (x ^ 2 - 3x + 2) and (5x ^ 2 - 3x - 8)

6x^2-6x-6

Step-by-step explanation:

(x^2-3x+2)+(5x^2-3x-8)

x^2+5x^2-3x+(-3x)+2+(-8)

6x^2-3x-3x+2-8

6x^2-6x+2-8

6x^2-6x-6

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step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length