QUICK PLS ASSESSMENT ENDS IN 30 mins The lengths of nails produced by a machine are known to be distributed normally
with mean u mm and standard deviation 0.7 mm. The lengths, in mm, of a
random sample of 5 nails are 107.29, 106.56, 105.94, 106.99, 106.47.
Calculate the 80% confidence interval for u.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

236 cm 16 time 12 = 192

6 times 7 = 42

192+42