At fast food restaurant, 90% of the customers’ order hamburger. If 72% of the customer’s order hamburger and French fries, what is the probability that a customer who orders hamburger will also order French fries?

0.8

Step-by-step explanation:

A = hamburger

B = french fries

P(B|A)

P(AB)/P(A)

= 0.72/0.9

= 0.8

y > 1/3x

y < = -x + 4

hope this : )

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3