What is the value of 3.5 (11) + 1.9 (11) + 1.6 (11)?
A.40
B. 77
C.4,096
D.9,317

I’m stuck on this i don’t understand.

The weights of players in a basketball league are distributed normally. the distance (d) of each player's weight (w) from the mean of 86 kilograms was computed as follows: d = |w - 86| if d is greater than 7 for approximately 5% of the players, what is the approximate standard deviation of the players' weights? a. 1.75 kilograms b. 3.5 kilograms c. 4.3 kilograms d. 7 kilograms

Find the distance between (0,5) & (-4,2)