The length of a rectangle is 6 metres more than its breadth. the perimeter of the rectangle is 60 metres . find the length and breadth of the rectangle.

The length of a rectangle is 6 metres more than its breadth. the perimeter of the rectangle is 60 metres . find the length and breadth of the rectangle.

We know:

Perimeter = 2(L+B)

by using this formula we can find value of x.

Let's Verify whether value of x is correct or not

insert Value of x

Hence verified

First let's find value of length :

Now Let's find value of breadth:

Given :

To find :

Solution :

As it is given that the length of rectangle is 6 m more than the breadth.

Thus, let us consider the Breadth as ''x''.

Then the Length will be ''x+6''.

We know that,

Perimeter of rectangle = 2(l + b)

According to Question,

➠Perimeter of rectangle = 2(x+6+x)

➠60 = 2(x+6+x)

➠60 = 2(x+x+6)

➠60 = 2(2x + 6)

➠60 = 4x + 12

➠60 - 12 = 4x

➠48 = 4x

➠48/4 = x

➠12 = x

∴ We got the Value of Breadth as 12 m, because we have let the breadth as x.

And the Length of the rectangle will be,

↠x + 6

↠12 + 6

↠18 m

Hence,

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step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value