Use a graph to find x and y values that make both y = x + 3 and y = 2x – 5 true.
YA
6
5 4
NW
-8 7 6 5 4 3 -2 -10
NE
4
6 7 8 x
-2
-3
The x-value is
The y-value is
The solution is

Step-by-step explanation:

The given equations are :

y = x + 3 .....(1)

y = 2x – 5 ......(2)

The table for equation (1) is :

x = 0, 1, 2, 8

y = 3, 4, 5, 11

The table for equation (2) is :

x = 0, 1 , 2, 8

y = -5, -3, -1, 11

From the graph we can see that,

The x-value is = 8

The y-value = 11

The solution is = (8,11).

idk

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629