Which sequence represents the function f(x)=x−3, with a domain of natural numbers? A) {4,5,6,7,…}
B) {−3,−6,−9,−12,…}
C) {−2,−1,0,1,…}
D) {−3,−2,−1,0,…}

C.

Step-by-step explanation:

The natural numbers are 1, 2, 3, 4

f(x) = x - 3 gives

1-3, 2-3, 3-3, 4-3 ..

= -2, -1, 0, 1 ..

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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