Trey drove to the mountains last weekend. There was heavy traffic on the way there, and the trip 8 took hours. When Trey drove home, there was no traffic and the trip only took 6 hours. If his average rate was 16 miles per hour faster on the trip home, how far away does Trey live from the mountains?

Trey lives 384 feet.

Step-by-step explanation:

Let the average rate be represented by s, and the distance by d.

speed =

⇒ distance = speed x time

i.e d = s x t

On his first trip,

d = s x 8

d = 8s ............ 1

on his trip home, the average rate was 16 miles per hour faster, so that;

d = (s + 16) x 6

d = 6s + 96 ............ 2

Equation 1 and 2, we have;

8s = 6s + 96

8s - 6s = 96

2s = 96

s = 48

The average rate is 48 miles per hour.

Thus from equation 1 (also equation 2 can be used),

d = 48 x 8

  = 384

Therefore, Trey lives 384 feet from the mountains.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

15% chance.

step-by-step explanation:

3/10 times, the 5 year old will get a tablet. 5/10 times, the 13 yer old will get a tablet. multiply both fractions to get 15/100 times, both would have a tablet.