For what value of “x” is the figure the given special parallelogram?

x = 6

Step-by-step explanation:

(In reference to my diagram.... my diagram is similar to the diagram in the question)

We know that diagonals of a square bisect each other at right angles.

In ΔBOC ,

•OB = OC (Diagonals of square bisect each other)

=> ∠OBC = ∠OCB = (7x + 3)°        (∵ OB = OC)

• ∠BOC = 90° (Diagonals intersect at right angles)

Using angle sum property of triangle ,

∠OBC + ∠OCB + ∠BOC = 90°

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!