What is the fifth term of the geometric sequence whose first three terms are 486, 162, and 54? a. 2
b. 3
c. 4.5
d. 6
e. 9

6

Step-by-step explanation:

an = ar^(n-1)

a = first term

n = nth term

r = common ratio

r = r2 / r1 = r3 / r2

The first 3 terms are :

486, 162, and 54

Hence,

a = 486

r = 162 / 486 = 1/3

Hence ;

a5 = 486(1/3)^5 - 1

a5 = 486(1/3)^4

a5 = 486(1 / 81)

a5 = 486 * 1 / 81

a5 = 486 / 81

a5 = 6

The 5th term of the geometric progression will be ; 6

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

what i would say the best answer is a. 40.5