A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the blag, what is the
probability that the first marble will be green and the second will be red?

number of green ÷ total number of marbles

times by

number of red ÷ total number of marbles left

so

(3/9) × (2/8) = (1/12)

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement