Does anyone knows how to solve this?

see explanation

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

= -

y = x² - 8x + 13 ← is in standard form

with a = 1 and b = - 8 , then

= - = 4

Substitute x = 4 into the equation for corresponding value of y

y = 4² - 8(4) + 13 = 16 - 32 + 13 = - 3

Vertex = (4, - 3 )

The axis of symmetry is a vertical line passing through the vertex with equation

x = 4 ← equation of axis of symmetry

To determine direction of opening

• If a > 0 then graph opens up

• If a < 0 then graph opens down

Here a = 1, thus graph opens up

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

there is nothing below so i cannot

step-by-step explanation: