A gardener who wants a rectangular garden whose lot perimeter is 40 meters is suggested by a fellow gardener a plan that would make it so that the build would have a maximum lot area. What could be the suggestion? You must answer in a mathematical solution. Show work.

a*(20-a)

Step-by-step explanation:

Let's assume that the length of the garden is a the width is b and the area is s.

b = 40/2 - a = 20-a

s =a*(20-a)=-a^2+20a=-(a-10)^2+100

then,

when a=10, max(-(a-10)^2) =0, max(s)=100

you estimate that the angle of elevation to the top of the 86th floor (the observatory) is 82 .the total height of the building is another 123 meters above the 86th floor.

leave feedback if u need : )

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200