If f(0)=287 and 5+4i is a root, what is the standard form of the polynomial function?

For f(0)=287, therefor it is

f(x)=sometingx+287 since the x's cancel for f(0)

5-4i and 5+4i

(x-(5-4i)) and (x-(5+4i))

(x-5+4i)(x-5-4i)

x^2-10x+41

right now, f(x)=41

41*what=287

Divide both sides by 41

what=7

time whole equation by that

f(x)=7(x^2-10x+41)

f(x)=7x^2-70x+287