What is the equation of the line that has a slope of 13 and goes through the point (6,−2)? y=13x−4

y=13x−8

y=13x+4

y=13x

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

unless if u could do my questions, if not i wouldn't want to