I have combined function c(t)= 300t + 19000(0.995)^t. t represents how long (hours) a hose runs, while 19000(0.995)^t represents evaporation of a pool (by hour). The pools total capacity is 20500 gallons. How many hours will the hose have to run so that the pool is filled to it's maximum capacity? Preferably, I'd like to know how to solve it... My workbook says to use calculator though (TI-84) so can anyone tell me how to solve it with that at least? Moving the tracer thing doesn't work because I can't get it to be on 20500.

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

so, converting firstly the mixed fractions to improper fractions and then "adding".

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb