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Mathematics, 11.01.2021 04:30 wehack523

Write an equation in slope-intercept form thats perpendicular to the given line and goes thru the point. 1. y=-3x + 4 (6,-2)
2. -2x -8y = 16 (4,5)
3.. x+y= 2 (8,5)
(PLS HELP ME I NEED THE ANSWER RIGHT NOW ITS URGENT)

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Answers: 1

Answers

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Answer from: xaguilar

steps below

Step-by-step explanation:

1.   y=-3x + 4            (6,-2)

y' slope: 1/3   (perpendicular)

y' = mx + b

b = y' - mx = -2 - (1/3) x 6 = -4

equation: y' = 1/3 x - 4

2.  -2x -8y = 16             (4,5)

8y = -2x - 16          y = -1/4 x - 2

perpendicular line slope: 4

b = y - mx = 5 - 4 x 4 = - 11

equation: y = 4x - 11

3. x+y= 2             (8,5)

y = -x + 2     slope: -1

perpendicular slope: 1

b = y - mx = 5 - 1 x 8 = -3

equation: y = x -3

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Answer from: Quest
C. i believe it is (5×(-20))+(100×(0.7))
30 points! the steps to simplify the expression are shown below, with one step missing. which is th
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Answer from: Quest
There was 504 pages in that chunk

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