A machine cell uses 204 pounds of a certain material each day. Material is transported in vats that hold 34 pounds each. Cycle time for the vats is about 2.25 hours. The manager has assigned an inefficiency factor of .17 to the cell. The plant operates on an eight-hour day. How many vats will be used

2 Vats will be used

Step-by-step explanation:

using the formula below, the ideal number of Kanban cards can be calculated;

N = (DT × ( 1 + X)) / C

where N is total number of container,

D is panned usage rate of using work Centre

T is Average waiting time for replenishment of parts plus average production for a  container of parts,

X is policy variable set by management that reflects possible inefficiency in the system ,

C is capacity of standard container.

Now, in the question, we were given that;

D = 204 pounds per day  = 204 / 8hrs = 25.5 pounds/hr   { The plant operates on an eight-hour day}

T = 2.25 hrs

X = 0.17

C = 34 pounds each

we substitute

N = (25.5×2.25 × ( 1 + 0.17)) / 34  

N = 67.12876 / 34

N = 1.974375 ≈ 2 Vats

Therefore 2 Vats will be used.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

10.4 inches

step-by-step explanation:

2x2x2.6