Which situation describes a variable rate of change in distance relative to time? A. A car accelerates from a speed of 45 miles per hour to a speed of 55 miles per hour. B. A bicyclist travels at a speed of 12 miles per hour.
C. A man walks at a speed of 3 miles per hour.
D. An airplane is parked on the runway.

Find the zero function by factoring (try to show work) h(x)=-x^2-6x-9

How do i simply this expression (quadratic formula basis) on a ti-84 or normal calculator?

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .