Write the point-slope form of the equation of the line using the point (-4,-2)

Note: Maybe you either forgot to mention the slope or forgot to mention another point from which the equation of the line passes.

In the later part, I would assume the slope m = 2 as an example.

Please check the explanation.

Step-by-step explanation:

Given

The point-slope form:

The point-slope form of the line equation is defined as

where

In our case:

(x₁, y₁) = (-4, -2)

substituting the point (-4, -2) in the point-slope form of the equation of the line

Therefore,  the point-slope form of the equation of the line using the point (-4,-2) will be:

BONUS!

Example Solving with assuming the slope m = 2

Let suppose the slope m = 2

As we have already got the equation in the point-slope form

substituting m = 2

Subtract 2 from both sides

Thus, the point-slope form of the equation of the line using the point (-4,-2) and having slope m = 2.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12