Please help!! i also need to show work.

write in vertex form y = -3x^2 - 18x + 12

3(-x^2-6x+4)

Step-by-step explanation:

-3x^2 - 18x + 12

-3x^2 - (2 x 3^2) x + 2^2 x 3

3 (-3x^2 over 3 - 2x3^2 times x over 3 + 262 x 3 over 3)

3(-(x^2) - (2 x 3^2-1 times x) +2^2

3(-x^2 - (2 times 3x) +4)

3(-x^2-(6x) + 4)

3(-x^2 - 6x + 4)

it would be 6xy and -16xy.

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.