A company has two manufacturing plants with daily production levels of 6x + 13 items and 3x - 7 items, respectively. The first plant produces how many more items daily than the second plant?

The first plant produces 3x+20 more items daily than the second plant.

Step-by-step explanation:

Given that:

Production level of first plant = 6x+13

Production level of second plant = 3x - 7

We will find the difference of both plants manufacture levels.

Difference = First plant - Second Plant

Difference = (6x+13)-(3x-7)

Difference = 6x+13-3x+7

Difference = 3x+20

Hence,

The first plant produces 3x+20 more items daily than the second plant.

10000000000000000000000000000000

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1