A Caribbean resort has a nightly limbo contest on the beach, Participants must be less than 64 inches tall. The distribution of heights of adult American men is approximately normal with mean 69 inches and standard deviation 2.5 inches. About what percent of adult American males could enter this contest?

2.23%

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = < 64 inches

μ is the population mean = 69

σ is the population standard deviation = 2.5

Since: Participants must be less than 64 inches tall.

For x < 64 inches

z = 64 - 69/2.5

z = -2

Probability value from Z-Table:

P(x<64) = 0.02275

Converting to percentage

= 0.02275 × 100

= 2.275%

Approximately = 2.23%

Because participants must be less than 64 inches tall to participate in this limbo contest, the percent of adult American males thag could enter this contest is 2.23%

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles